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Question: 1 / 400

What is the value of 3y^2 - 2x + 4z when x=3, y=-4, and z=2?

-13

13

50

To find the value of the expression 3y² - 2x + 4z using the given values of x, y, and z, substitute each variable into the expression.

Start by substituting y = -4 into the term 3y²:

3(-4)² = 3(16) = 48.

Next, substitute x = 3 into the term -2x:

-2(3) = -6.

Finally, substitute z = 2 into the term 4z:

4(2) = 8.

Now combine these results:

48 (from 3y²) - 6 (from -2x) + 8 (from 4z) = 48 - 6 + 8.

Calculating that gives:

48 - 6 = 42.

Then, 42 + 8 = 50.

Therefore, the correct answer is 50.

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