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Question: 1 / 400

An equation of the line that contains the origin and the point (1, 2) is

2y = x

To find the equation of the line that contains the origin (0,0) and the point (1,2), we can use the point-slope form of the equation of a line which is \( y - y_1 = m(x - x_1) \), where \( (x_1, y_1) \) is a point on the line and \( m \) is the slope of the line.

Here, the point (1,2) lies on the line. We calculate the slope using the formula \( m = \dfrac{y_2 - y_1}{x_2 - x_1} \) by substituting the coordinates of the two points:

\( m = \dfrac{2 - 0}{1 - 0} = 2 \).

Now, we substitute the slope and the given point (1,2) into the point-slope form:

\( y - 2 = 2(x - 1) \).

Upon simplifying this equation, we get \( y = 2x - 2 \), or in the form given in choice A: \( 2y = x \). Hence, choice A is the correct answer.

The

Get further explanation with Examzify DeepDiveBeta

y = x - 1

y = 2x + 1

y/2 = x - 1

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